±Û¾´ÀÌ: jinzzadan (aurora86)
³¯ Â¥: Thu Aug 28 22:27:12 2003
Á¦ ¸ñ: Re: Àß ¸ø µÈ°ÍÀº?
>>>>> "pbseoyu"´ÔÀÌ "Àß ¸ø µÈ°ÍÀº?"¿¡¼ ¾²±æ:
pbseoyu> -4=-2^2=-2^6/3=(-2^6)^1/3=64^1/3=(4^3)^1/3=4 °í·Î -4=4??????
bluechess´Ô (2003/05/03)
bluechess> -(2^6) = -64 ȤÀº -4 = -(2^2)
(-2^6)^1/3=64^1/3 À̺κÐÀÌ À߸øµÈ °ÍÀÌ ¾Æ´Ñ°¡¿ä?
ÀÌ ½ÄÀÇ Áº¯À» Á¤¸®ÇØ º¸¸é: (-2^6)^1/3 = (-64)^1/3 = -4·Î Á¤¸®µÇ¾î¾ß ÇÒ °Í °°Àº
µ¥¿ä...
qwerasdf´Ô (2006/08/29)
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